9x^2+26x-486=0

Solution for 9x^2+26x-486=0 equation:

9x^2+26x-486=0

a = 9; b = 26; c = -486;
Δ = b2-4ac
Δ = 262-4·9·(-486)
Δ = 18172
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18172}=\sqrt{4*4543}=\sqrt{4}*\sqrt{4543}=2\sqrt{4543}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-2\sqrt{4543}}{2*9}=\frac{-26-2\sqrt{4543}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+2\sqrt{4543}}{2*9}=\frac{-26+2\sqrt{4543}}{18}
$